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x^2+2x-3/x^2-1 ....with steps please :)
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factorize.
(x-1) (x+3) ---------- (x-1) (x+1)
(x+3) ------ (x+1)
ok first step u factor the numerator and the denominator which becomes (x+3)(x-1) /(x-1)(x+1) and then simplify x-1 with x-1 so the answer is (x+3)/x+1
Thanks Saifoo and Aroub!
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Uw Brian! ;)
anytime brian! :D
Actually, how do you know that \[(x ^{2}-1) \] is not written as (x-1)(x-1) but it is written as (x-1)(x+1) ?
YES x^2-1 is (x-1)(x+1)
yes i know, but why can we not write it as (x-1)(x-1)..what is the rule for it?
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oh okay the rule is (a^2-b^2) =( a-b)(a+b)
oh and the sign must be negative!
Ohh okay that makes sense, Thanks!!
no prob! :)
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