Question

prove that for all v.v = |v|squared for all v E R cubed

Answer 1

pretend
we have v=<-3,0,4>
|v|=sqrt{9+0+16}=sqrt{25}=5
|v|^2=25

but 25 does not equal <-3,0,4>

that is why im saying the statement is false and i cannot prove it
i can only provide you with this counterexample (and more if you like)

Answer 2

|v| means the magnitude of the vector (or length)
do you understand what i'm saying?

the length cannot be =to the vector unless the vector is a 1 by 1 vector

Answer 3

if you are using the dot product then it is true that

\[v\cdot v=|v|^2\]

Answer 4

\[v=<v_1,v_2,v_3>\]

\[v\cdot v=v_1\times v_1+v_2\times v_2+v_3\times v_3=v_1^2+v_2^2+v_3^3=|v|^2\]

Answer 5

oh is it v dot v?

Answer 6

I believe so...hard to tell with how the original question was asked.

Answer 7

i think you may be right
lol it has to be