Can anyone help me with only 5 questions of exponential decay? Pleaseeee i'll give medals :(
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jhonyy9 (jhonyy9):
goooo
jhonyy9 (jhonyy9):
where are ???
OpenStudy (anonymous):
why is your picture a pic of your butt?
OpenStudy (anonymous):
yummmm
OpenStudy (anonymous):
A farmer in china discovers a mammal hide that contains 71% of its original amount of C-14.
Find the age of the mammal hide to the nearest year.
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OpenStudy (anonymous):
do you know the half life or carbon 14?
OpenStudy (bahrom7893):
e^(-kt) = 0.41
OpenStudy (bahrom7893):
wait sorry
e^(-kt) = 0.71
OpenStudy (bahrom7893):
kt = ln(1/0.71) = ln(1.408)
OpenStudy (anonymous):
i think it is 5700 years. if so solve
\[.71=(\frac{1}{2})^{\frac{t}{5700}}\] for t via
\[\ln(.71)=\frac{t}{5700}\ln(.5)\]
\[t=5700\times \frac{\ln(.71)}{\ln(.5)}\]
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OpenStudy (anonymous):
i get 2816 years
OpenStudy (bahrom7893):
k= 0.0001
t = ln(1.408)/0.0001 = 3421
OpenStudy (bahrom7893):
I got that, but I think satellite must be right
OpenStudy (anonymous):
no k is not .0001 that is rounding error
OpenStudy (bahrom7893):
oh okay then satellite is right, i dunno the half life of C-14 just googled it and that was what i got
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OpenStudy (anonymous):
it is easier in these problems to work with half lives.