Question

Let f(x,y,z)=x+ln(2y+3z^2) Evaluate ∂^2f/∂y∂x (2,1,-2)

Answer 1

∂^2f/∂y∂x=(∂f/∂y)x(∂f/∂x)
∂f/∂y=2/(2y+3z^2)
∂f/∂x=1
so ∂^2f/∂y∂x=2/(2y+3z^2)=1/5

Answer 2

thanks i thought it was 0

Answer 3

your welcme

Answer 4

is it 1/7??