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Find f '(x) if f(x) = (cos (sin(x^2)))^3
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-6.x.cos(x^2).sin(sin(x^2)).(cos(sin(x^2))^2
We'll use chain rule to differentiate with respect to x: f'(x) = 6x*(cos(sin x^2))^2*(-sin(sin x^2))*(cos x^2)
can you explain the chain rule to me? Im so confused with that area
isnt it -6? O.o Is that a mistake ? :P
I may be wrong lol
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we consider the given function as a result of composition of 4 functions. the power function (cosine raised to cube), then cosine function, sine function and the monomial x^2. You'll have to differentiate each function with respect to x.
yes -6
yes, -6
Thank you!
No, no no. Thank YOU!
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