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Mathematics 16 Online
OpenStudy (anonymous):

Find f '(x) if f(x) = (cos (sin(x^2)))^3

OpenStudy (anonymous):

-6.x.cos(x^2).sin(sin(x^2)).(cos(sin(x^2))^2

OpenStudy (anonymous):

We'll use chain rule to differentiate with respect to x: f'(x) = 6x*(cos(sin x^2))^2*(-sin(sin x^2))*(cos x^2)

OpenStudy (anonymous):

can you explain the chain rule to me? Im so confused with that area

OpenStudy (anonymous):

isnt it -6? O.o Is that a mistake ? :P

OpenStudy (anonymous):

I may be wrong lol

OpenStudy (anonymous):

we consider the given function as a result of composition of 4 functions. the power function (cosine raised to cube), then cosine function, sine function and the monomial x^2. You'll have to differentiate each function with respect to x.

OpenStudy (anonymous):

yes -6

OpenStudy (anonymous):

yes, -6

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

No, no no. Thank YOU!

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