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OpenStudy (anonymous):
\[\frac{x+10}{(x-2)(x+4)}=\frac{A}{x-2}+\frac{B}{x-4}\] is this what you want?
OpenStudy (anonymous):
YEA LOL THANKS
OpenStudy (anonymous):
oops that is backwards. sorry
OpenStudy (anonymous):
let me do that again i had it backwards
OpenStudy (anonymous):
THE 4 ARE + 4 NOT _
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OpenStudy (anonymous):
you need the method or just the answer?
OpenStudy (anonymous):
ok let me try one more time
OpenStudy (anonymous):
METHOD AND ANSWER PLZ
OpenStudy (anonymous):
ok first the answer
\[A=2,B=1\]
OpenStudy (anonymous):
now method. if you were going to add
\[\frac{A}{x-2}+\frac{B}{x+4}\] your numerator would be
\[A(x+4)+B(x-2)\] and you know your numerator is
\[x+10\] so set
\[(x+4)A+(x-2)B=x+10\]
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OpenStudy (anonymous):
this has to be an identity for all x so you get to pick any x to solve for A and B. put
\[x=2\] gete
\[(2+4)A+(2-2)B=2+10\]
\[6A=12\]
\[A=2\]
OpenStudy (anonymous):
YOUR SMART THAMKS
OpenStudy (anonymous):
now guess what you pick for x? pick
\[x=-4\] get
\[(-4+4)A+(-4-2)B=-4+10\]
\[-6B=6\]\[B=-1\]