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OpenStudy (anonymous):
3-3sq
OpenStudy (anonymous):
I think you missed something when you foiled. I have:
\[-9s ^{2}q ^{2}-6sq+6\]
OpenStudy (anonymous):
Is it
\[(2+3^2)(3-3^2)\]
OpenStudy (anonymous):
Or are s and q variables?
OpenStudy (anonymous):
Now that you mention it, I think you're right mkuehn
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OpenStudy (anonymous):
Used to looking for complicated problems ;)
OpenStudy (anonymous):
It could reallly be either, but sq seems a bit too "convenient" :)
OpenStudy (anonymous):
the 3 have this sign\[\sqrt{3}\]
OpenStudy (anonymous):
waht is that
OpenStudy (anonymous):
That changes things :)
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OpenStudy (anonymous):
That is the square root. If you take the square root of a number, the answer you get is a number times itself that equals that number.
For example, the square root of 4 is equal to 2 because 2 x 2 = 4
OpenStudy (anonymous):
\[(2+\sqrt{3})(3-\sqrt{3})\]
OpenStudy (anonymous):
\[\sqrt{3}+3\]
OpenStudy (anonymous):
yea like that
OpenStudy (anonymous):
When you foil you end up with:
\[6-2\sqrt{3}+3\sqrt{3}-3\]
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OpenStudy (anonymous):
idk how you got 6
OpenStudy (anonymous):
It is 2 times 3.
OpenStudy (anonymous):
The -3 came from:
\[-\sqrt{3}*\sqrt{3}=-3\]
OpenStudy (anonymous):
ok goy u
OpenStudy (anonymous):
got it .plz keep going
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OpenStudy (anonymous):
You just combine like terms. In this case combine the (6 - 3) and the 3sqrt(3) - 2sqrt(3)
OpenStudy (anonymous):
So you are left with 3 + 3sqrt(3)
OpenStudy (anonymous):
The answer is above the expansion if you scroll up. I combined like terms. Think of \[\sqrt{3}\] as an x when combining like terms.