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Mathematics 10 Online
OpenStudy (anonymous):

If M is chosen at random on segment AF. Find the probability that M is on segment AC

OpenStudy (anonymous):

pic?

OpenStudy (anonymous):

a)5/18 b)1/6 c)7/18 d)1/9

OpenStudy (anonymous):

is all of that correct? because if it is then none of those answers are correct. a is supposed to be at point 0 right?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

well the formula for probablility is (number of desired outcomes)/(number of total possible outcomes) since there are 19 points on the line, then the denominator is 19. and since there are 6 points on AC then the numerator should be six. so what i get is: 6/19 but that doesnt seem to be one of the possible answers

OpenStudy (anonymous):

idk?

OpenStudy (anonymous):

ahh good, joe math is here, he should know something i don't

OpenStudy (anonymous):

perhaps

OpenStudy (anonymous):

its 5/18, while there are 19 points on the line, the space between 0 and 18 (the length AF) is 18 units long, while the space between 0 and 5 (the length AC) is 5 units long. So im going with 5/18

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

i was totally with Napervillian at first though, i had to go back and check the picture lol.

OpenStudy (anonymous):

i'm still confused but as long as you get the right answer it's all good! lol

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

ahhh...now i get it

OpenStudy (anonymous):

plz help me with my last ?

OpenStudy (anonymous):

joe math win

OpenStudy (anonymous):

whats your next question?

OpenStudy (anonymous):

Find that probability that a point chosen at random in the figure lies in the green area.

OpenStudy (anonymous):

is there a new pic that goes with this?

OpenStudy (anonymous):

a)75.3% b)77.1% c)79.4% d)83.2%

OpenStudy (anonymous):

step 1: find the total area of the solid so: (5x13)+(6x11) -- since we dont want to take the area of the white part twice 65+66 131 step 2: find the area of the green part: (6x11)+(5x7) 66+35 101 step 3: set up your probablility equation: 101/131

OpenStudy (anonymous):

b)77.1

OpenStudy (anonymous):

perfect :) i had a picture drawn, but for some reason the software i use to upload scans is bugging on me. gotta reboot. I'll post it when im back online. Napervillians solution is spot on though :)

OpenStudy (anonymous):

win! one for two, lets see if i can up the ratio

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

both!!!

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