If M is chosen at random on segment AF. Find the probability that M is on segment AC
pic?
a)5/18 b)1/6 c)7/18 d)1/9
is all of that correct? because if it is then none of those answers are correct. a is supposed to be at point 0 right?
yep
well the formula for probablility is (number of desired outcomes)/(number of total possible outcomes) since there are 19 points on the line, then the denominator is 19. and since there are 6 points on AC then the numerator should be six. so what i get is: 6/19 but that doesnt seem to be one of the possible answers
idk?
ahh good, joe math is here, he should know something i don't
perhaps
its 5/18, while there are 19 points on the line, the space between 0 and 18 (the length AF) is 18 units long, while the space between 0 and 5 (the length AC) is 5 units long. So im going with 5/18
thank you
i was totally with Napervillian at first though, i had to go back and check the picture lol.
i'm still confused but as long as you get the right answer it's all good! lol
:)
ahhh...now i get it
plz help me with my last ?
joe math win
whats your next question?
Find that probability that a point chosen at random in the figure lies in the green area.
is there a new pic that goes with this?
a)75.3% b)77.1% c)79.4% d)83.2%
step 1: find the total area of the solid so: (5x13)+(6x11) -- since we dont want to take the area of the white part twice 65+66 131 step 2: find the area of the green part: (6x11)+(5x7) 66+35 101 step 3: set up your probablility equation: 101/131
b)77.1
perfect :) i had a picture drawn, but for some reason the software i use to upload scans is bugging on me. gotta reboot. I'll post it when im back online. Napervillians solution is spot on though :)
win! one for two, lets see if i can up the ratio
thank you
both!!!
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