Question

Solve for s
6q + 2/9r = 6q +1/9s

2r + 12q, right?

Answer 1

Let me have a look...

Answer 2

Can't see how u got that, sorry.

Answer 3

then wat's the answer?

Answer 4

is this the question?
\[\frac{6q+2}{9r} = \frac{6q+1}{9s}\]

Answer 5

no its

Answer 6

\[6q+\frac{2}{9r} = 6q +\frac{1}{9s}\]
?

Answer 7

right answer is : 8s+9r=0

Answer 8

yes! tht's it, joe!!!!

Answer 9

oh the question is that which joe wrote there???

Answer 10

alright, so first, because there is a 6q on both sides of the equation, we can subtract 6q from both sides and get rid of them:
\[6q+\frac{2}{9r} = 6q+\frac{1}{9s} \Rightarrow \frac{2}{9r} = \frac{1}{9s}\]
Does that make sense to you?

Answer 11

yesh

Answer 12

the final answer is 9r=18s ==> 9r-18s=0

Answer 13

nice, now that we have gotten rid of those 6q's, we just have fractions left, and we can cross multiply:\[\frac{2}{9r} = \frac{1}{9s} \Rightarrow 2*9s = 1*9r \Rightarrow 18s = 9r\]

Answer 14

okay

Answer 15

The last thing we need to do in order to solve for s is to get rid of that 18 that is multiplying the s. So we divide both sides by 18:
\[18s = 9r \Rightarrow s = \frac{9r}{18}\]
then we reduce that fraction for the final answer:
\[s = \frac{9r}{18} \Rightarrow s = \frac{r}{2}\]

Answer 16

writing it like that or like:
\[\frac{1}{2}r\]
is acceptable. If there are any steps you are confused with or want me to explain further let me know :)