Find the points at which the graph of the equation has a vertical or horizontal tangent line. 4x2 + 16y2 – 72x – 96y + 404 = 0 horizontal tangents (x, y) = vertical tangents (x, y) =
and satellite i wnated to thankyou again but my comp froze..lol..please help me on this one as well:)
sattelite can you please help me out on this one...
sure
oh man another implicit diff? hold on i will write it out on paper
Find the points at which the graph of the equation has a vertical or horizontal tangent line. (Order your answers from smallest to largest x, then from smallest to largest y.) 4x2 + 16y2 – 72x – 96y + 404 = 0 horizontal tangents (x, y) = ( ), ( ) vertical tangents (x, y) = ( ), ( )
oki cool...thankyou so much for this thought...a guy by the name of bahrom recomended you:)
yeah i got it.
horizontal tangent when x = 9
vertical when y = 3
put in x = 9 to find the corresponding y and vice versa
leme try
try the x i will try the y = 3
k..im confused about where and how to plug it in
i got x = 9 you need y. replace x by 9 in original equation to find y
oki
ugh im confused i know what you saying but im screwing up the algebra:(
damn i get no answer. let me try again
oki
ok i got this \[y'=\frac{8x-72}{96-32y}\] and i am fairly certain this one is right
because i did it twice. horizontal tangent means numerator = 0 so i set \[8x-72=0\] get \[x=9\]
the problem is when i replace x by 9 in original equation and solve for y i get no solution
wait but its asking for points
ok here is the answer
so what would the pooint sets be:S
horizontal, x = 9, y = 1
vertical x = 5, y = 3
oh wait. there are two for each
its saying thats inccorect
maybe theres 4 sets of points
so here is final answer: horizontal x=9, y = 1 x = 9, y = 5 vertical x = 5, y = 3 x = 13, y = 3
it is an ellipse so two vertical and two horizontal ones algebra is a pain pain pain
:)...yes omg thankyou
please don't tell me that was wrong
oh whew
no it was right lol hence im saying thanks
do u mind helkping me on anything els..i have a few from another section too
i have about another 15 minutes in me
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