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OpenStudy (anonymous):
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.
y = √x
(a) Find dy/dt, given x = 16 and dx/dt = 7.
dy/dt =
(b) Find dx/dt, given x = 64 and dy/dt = 8.
dx/dt =
14 years ago
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OpenStudy (anonymous):
y = √x
(a) Find dy/dt, given x = 16 and dx/dt = 7.
dy/dt =
(b) Find dx/dt, given x = 64 and dy/dt = 8.
dx/dt =
14 years ago
OpenStudy (anonymous):
\[\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}\]
14 years ago
OpenStudy (anonymous):
hey satelitte:)
14 years ago
OpenStudy (anonymous):
put in x = 16 and dx/dt=7 to get your answer!
14 years ago
OpenStudy (anonymous):
you get
\[\frac{dy}{dt}=\frac{1}{2\sqrt{16}}\times 7\]
14 years ago
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OpenStudy (anonymous):
or
\[\frac{dy}{dt}=\frac{7}{8}\]
14 years ago
OpenStudy (anonymous):
for the second one put
\[8=\frac{1}{2\sqrt{64}}\times \frac{dx}{dt}\] and solve
14 years ago
OpenStudy (anonymous):
i get
\[\frac{dx}{dt}=128\]
14 years ago
OpenStudy (anonymous):
yes!!!:)..ur a complete life saver today you have no idea.god bless you!:)
14 years ago
OpenStudy (anonymous):
yw
14 years ago
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OpenStudy (anonymous):
just pass your class ok?
14 years ago
OpenStudy (anonymous):
yeh im trying..ur helping me out and i appreciate it alot
14 years ago
OpenStudy (anonymous):
i absolutely loved jennifer's body. laughed my @ss off. maybe favorite horror movie of 2009
14 years ago
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