Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. y = √x (a) Find dy/dt, given x = 16 and dx/dt = 7. dy/dt = (b) Find dx/dt, given x = 64 and dy/dt = 8. dx/dt =
y = √x (a) Find dy/dt, given x = 16 and dx/dt = 7. dy/dt = (b) Find dx/dt, given x = 64 and dy/dt = 8. dx/dt =
\[\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}\]
hey satelitte:)
put in x = 16 and dx/dt=7 to get your answer!
you get \[\frac{dy}{dt}=\frac{1}{2\sqrt{16}}\times 7\]
or \[\frac{dy}{dt}=\frac{7}{8}\]
for the second one put \[8=\frac{1}{2\sqrt{64}}\times \frac{dx}{dt}\] and solve
i get \[\frac{dx}{dt}=128\]
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