if a taxi ride in 1990 costs $4.00 for the first 4km and 90cents for each additional kilometer or fraction thereof, then how much would a passenger pay for an 8 1/2km ride?

At 2:30p.m., the angle formed by the hands of a clock measures?

how to find this?
please include a picture if possible

Please answer clearly and explain the solution clearly and easy to understand. Thanks!
(guaranteed medal for a good answer)

what is fraction thereof?

Question

if a taxi ride in 1990 costs $4.00 for the first 4km and 90cents for each additional kilometer or fraction thereof, then how much would a passenger pay for an 8  1/2km ride?

At 2:30p.m., the angle formed by the hands of a clock measures?

how to find this?
please include a picture if possible

Please answer clearly and explain the solution clearly and easy to understand. Thanks!
(guaranteed medal for a good answer)

what is fraction thereof?

gw2011 · Answer

8.5 - 4 which is the first 4km = 4.5
(4km)($4) = $16
(4.5km)($0.90) = $4.05

$16 + $4.05 = $20.05 which is what the passenger pays

"Fraction thereof" means any fraction that is left to be calculated


A clock is a circle which has 360 degrees.  Since there are 12 numbers on a clock, divide 360 degrees by 12 to get 30 degrees between each number.  So, at 3:30 the angle formed is 90 degrees which means that one of the hands is horizontal (straight across) and the other hand is vertical (straight up).  Therefore, since the number 2 is above the number 3 by the 30 degrees, you add the 90 degrees and the 30 degrees to get 120 degrees.  Therefore, the angle formed at 2:30 is 120 degrees.  Sorry that I can't draw you a picture but I hope this explanation helps.

moongazer · Answer

why is it according to my book the answer for the clock problem is 105degrees. why?
and for the taxi it is 8.50 
you are wrong

gw2011 · Answer

For the clock problem I overlooked the fact that the one hand at 2:30 is half way between 2 and 3.  Therefore, since the hands form a right angle (90 degrees) when one is at 3 and the other is at 6 and each number is separated by 30 degrees, then you take one-half of 30 degrees which is 15 degrees and add it to the 90 degrees to get 105 degrees.

For the taxi problem I assumed that the $4 for the first 4km was for each km rather than a flat rate since the problem didn't state which one it was.  Therefore, the additional 4.5km will be multiplies by 90 cents to get $4.05.  Add the $4.05 to the flat rate of $4 for the first 4km adn you get $8.05.  The $8.50 is not correct--this must be a typo error.