Question

find four consecutive integers such that the product of the two largest is 46 more than the product of the two smallest ?

Answer 1

let the 4 integers be x, x+1, x+2,x+3
then
(x+2)(x+3) = y + 46
x(x+1) = y

now its a matter of solving these two equations

Answer 2

next step would be
(x+2)(x+3) = x(x+1) + 46

Answer 3

or the next step is enter those 2 things into a graphing calculator and find the intersection, which is x = 10, y = 110

Answer 4

expanding

x^2 + 5x + 6 = x^2 + x + 46
5x - x = 46 - 6
4x = 40
x = 10
- the rest is easy

Answer 5

do u follow that ok?

Answer 6

im doing it

Answer 7

if you're feeling extra awesome and redundant, you could even put it into an augmented matrix and solve it that way, lol

Answer 8

yep