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OpenStudy (anonymous):
Find cos theta in (pi/2,pi) so that cot theta = -12/5
15 years ago
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OpenStudy (anonymous):
what?
15 years ago
OpenStudy (anonymous):
It is impossible for the value of cosine of any angle to be larger than 1 and smaller than -1. We notiuce that cos theta = -12/5 = -2.4 < -1, therefore there is no value for theta in (pi/2 , pi)
15 years ago
OpenStudy (anonymous):
Cot theta...
15 years ago
OpenStudy (anonymous):
\[\frac{\text{Sin}[\theta ]}{\text{Cos}[\theta ]}=\frac{-5}{12}\]
15 years ago
OpenStudy (anonymous):
Ok, that's tan theta, so what's cos theta?
15 years ago
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OpenStudy (anonymous):
\[\frac{12}{-5} \text{Sin}[\theta ]=\text{Cos}[\theta ]\]
15 years ago
OpenStudy (anonymous):
I want a value...
15 years ago
OpenStudy (anonymous):
To find this value, you'll have to apply Pythagorean identity:
1 + (tan theta)^2 = 1/(cos theta)^2
(cos theta) = - sqrt [1/1 + (tan theta)^2]
15 years ago
OpenStudy (anonymous):
@giorgia
looks promising, so what is it then?
15 years ago
OpenStudy (anonymous):
You'll plug the value for tan theta and you'll raise to square:
(cos theta) = - sqrt [1/1 +144/25]
cos theta = -sqrt169/25
cos theta = -13/5
15 years ago
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OpenStudy (anonymous):
Nope.
15 years ago
OpenStudy (anonymous):
oh, yes!
15 years ago
OpenStudy (anonymous):
12/13 ?
15 years ago
OpenStudy (anonymous):
Think the problem is us have sqrt(1/1...) instead of
1/sqrt(1+
15 years ago
OpenStudy (anonymous):
@imranmeah
Close....check interval.
15 years ago
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OpenStudy (anonymous):
Sign of cos in second quadrant?
15 years ago
OpenStudy (anonymous):
-12/13
15 years ago
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