Find cos theta in (pi/2,pi) so that cot theta = -12/5
what?
It is impossible for the value of cosine of any angle to be larger than 1 and smaller than -1. We notiuce that cos theta = -12/5 = -2.4 < -1, therefore there is no value for theta in (pi/2 , pi)
Cot theta...
\[\frac{\text{Sin}[\theta ]}{\text{Cos}[\theta ]}=\frac{-5}{12}\]
Ok, that's tan theta, so what's cos theta?
\[\frac{12}{-5} \text{Sin}[\theta ]=\text{Cos}[\theta ]\]
I want a value...
To find this value, you'll have to apply Pythagorean identity: 1 + (tan theta)^2 = 1/(cos theta)^2 (cos theta) = - sqrt [1/1 + (tan theta)^2]
@giorgia looks promising, so what is it then?
You'll plug the value for tan theta and you'll raise to square: (cos theta) = - sqrt [1/1 +144/25] cos theta = -sqrt169/25 cos theta = -13/5
Nope.
oh, yes!
12/13 ?
Think the problem is us have sqrt(1/1...) instead of 1/sqrt(1+
@imranmeah Close....check interval.
Sign of cos in second quadrant?
-12/13
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