Question

can (10x^2-65x-21/2(2x+1)) be simplified

Answer 1

hmmm, well i dont think it can get any worse :)

Answer 2

see if the top factors to something that can be "canceled" with the bottom

Answer 3

simplest thing might be to divide the top by (2x+1) and if it has no remainder than its good to simplify

Answer 4

but there is a 2 in front of 2(x+1)

Answer 5

do i just leave the 2 alone

Answer 6

and there is no 2 that factors out of the top so its useless to us

Answer 7

we need to check of (2x+1) is a factor of the top

Answer 8

we can try to piece it togeher like this:

(2x+1) (ax + b) = 10x^2 -65x -21

2x+1
ax +b
---------------
(2b)x+b
(2a)x^2 +ax
-----------------
10x^2 -65x -21

b would have to equal -21 and a would have to equal 5 for it to have a chance to work out

Answer 9

now im confused

Answer 10

2x+1
5x -21
--------------
-42x -21
10x^2 +5x
---------------
10x^2 -37x -21 ..... which doesnt match up

Answer 11

5x -35
----------------
2x+1 |10x^2 -65x -21
-10x^2 -5x
---------------
-70x -21
70x +35
---------
doesnt = 0

Answer 12

id venture to say that it doesnt simplify

Answer 13

multiplying and dividing polynomials is just the same as doing it to numbers; same rules apply

Answer 14

what your prolly not used to seeing is the "place holders" in this format:

523 expands to 500 + 20 + 3; and if we allow x to equal 10 we get

5x^2 + 2x + 3 ; same number, different way of seeing it

Answer 15

so it is just 10x^2-65x-21/2(2x+1)