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OpenStudy (bahrom7893):
okay use this formula:
a^2-b^2=(a-b)(a+b)
OpenStudy (bahrom7893):
ur a=2x, b=3y
OpenStudy (anonymous):
difference of 2 squares
jimthompson5910 (jim_thompson5910):
This is a difference of squares: A^2-B^2=(A+B)(A-B)
In this case, A=2x and B=3y
So 4x^2-9y^2=(2x+3y)(2x-3y)
OpenStudy (bahrom7893):
Plug that in and get the answer, this is simple, you can doit yourself
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OpenStudy (bahrom7893):
and jim, guide them but don't post the answers, i think they should do it themselves.
OpenStudy (bahrom7893):
What I mean is tell them what to do.
OpenStudy (anonymous):
i really wish i understood all of this lol
jimthompson5910 (jim_thompson5910):
true, but I find it helps to step them through it
OpenStudy (bahrom7893):
sarsar56, you will need this in your future life.
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OpenStudy (anonymous):
it weill be (2x+3y)(2x-3y)
jimthompson5910 (jim_thompson5910):
if not sarsar, let me know
OpenStudy (anonymous):
9x^2+16 so how would id o this one
OpenStudy (bahrom7893):
Well jim we already factored a couple of problems. Like see what i mean, tell them to use this formula:
a^2-b^2 = (a-b)(a+b)
Tell them to observe that:
4x2 - 9y2 = (2x)^2-(3y)^2, and tell them to do the substitution to factor.
OpenStudy (bahrom7893):
Sarsar I don't think that's factorable.
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OpenStudy (bahrom7893):
Wait we can complete the square
jimthompson5910 (jim_thompson5910):
you can complete the square, but that won't make it factorable
OpenStudy (anonymous):
how do u know if something is not factorablw
OpenStudy (anonymous):
thi will be like this (3x+4)(3x-4)
OpenStudy (bahrom7893):
I think it can be factored
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jimthompson5910 (jim_thompson5910):
if you have a sum of squares, then it is NOT factorable.
OpenStudy (anonymous):
whats a sum of squares
OpenStudy (bahrom7893):
9x^2+16
(3x)^2 + 2*3x*4 + 4^2 - 2*3x*4
OpenStudy (bahrom7893):
(3x+4)^2-24x
jimthompson5910 (jim_thompson5910):
a square is any expression that can be represented by squaring another expression.
For example, 4 is a square of 2 since 2 squared = 4
Also, 4x^2 = (2x)^2 is another square
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OpenStudy (anonymous):
ouch i am sorry i thought there is minuse so sorry!!!
OpenStudy (bahrom7893):
And then:
(3x+4-sqrt(24x))(3x+4+sqrt(24x))
OpenStudy (bahrom7893):
I mean that just makes it uglier haha
jimthompson5910 (jim_thompson5910):
but when they say "factorable", they mean over the rationals.
jimthompson5910 (jim_thompson5910):
and you forgot the imaginary terms, which makes it even worse
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OpenStudy (bahrom7893):
oh i guess, i mean i never learned how u guys do it here in the US.
OpenStudy (anonymous):
i kind of see it but not really ):
jimthompson5910 (jim_thompson5910):
don't worry about it, 9x^2+16 is NOT factorable
OpenStudy (anonymous):
how about this one 2xy-xz+2wy-wz
OpenStudy (bahrom7893):
Okay sarsar observe what is similar in the equation
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OpenStudy (anonymous):
which would b the 2y?
OpenStudy (bahrom7893):
2xy-xz+2wy-wz
2xy+2wy-xz-wz
2y(x+w)-z(x+w)
OpenStudy (bahrom7893):
So:
(x+w)(2y-z)
OpenStudy (anonymous):
i think u can do like this : 9x^2 +9+7
then we wil factor : 9(x^2+1)+7
then:( 9+7)(x^2+1)
OpenStudy (anonymous):
am i right?
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OpenStudy (anonymous):
4ax + 8ay + 3bx + 6by
so like in this one, do i start by taking out the GCF?
jimthompson5910 (jim_thompson5910):
sorry Roh, that's not the correct factorization. You can verify that by expanding
OpenStudy (bahrom7893):
no u pulled out 9+7, u can't do that
jimthompson5910 (jim_thompson5910):
first, group terms
(4ax + 8ay) + (3bx + 6by)
jimthompson5910 (jim_thompson5910):
what comes next?
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OpenStudy (anonymous):
mmmm yeah ur right bahroom
OpenStudy (bahrom7893):
Jim where did u get that one from?
jimthompson5910 (jim_thompson5910):
which one?
OpenStudy (bahrom7893):
oh u just took it as an example? I see
was talkin about this (4ax + 8ay) + (3bx + 6by)
OpenStudy (anonymous):
ahhhhh im confused lol
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OpenStudy (bahrom7893):
I think ima leave, having too much people to help confuses others
OpenStudy (bahrom7893):
*too many
OpenStudy (anonymous):
yoou can factor it by group factoring sarsar no confusing is needed let me do it