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Mathematics 21 Online
OpenStudy (anonymous):

Factor: 4x2 - 9y2

OpenStudy (bahrom7893):

okay use this formula: a^2-b^2=(a-b)(a+b)

OpenStudy (bahrom7893):

ur a=2x, b=3y

OpenStudy (anonymous):

difference of 2 squares

jimthompson5910 (jim_thompson5910):

This is a difference of squares: A^2-B^2=(A+B)(A-B) In this case, A=2x and B=3y So 4x^2-9y^2=(2x+3y)(2x-3y)

OpenStudy (bahrom7893):

Plug that in and get the answer, this is simple, you can doit yourself

OpenStudy (bahrom7893):

and jim, guide them but don't post the answers, i think they should do it themselves.

OpenStudy (bahrom7893):

What I mean is tell them what to do.

OpenStudy (anonymous):

i really wish i understood all of this lol

jimthompson5910 (jim_thompson5910):

true, but I find it helps to step them through it

OpenStudy (bahrom7893):

sarsar56, you will need this in your future life.

OpenStudy (anonymous):

it weill be (2x+3y)(2x-3y)

jimthompson5910 (jim_thompson5910):

if not sarsar, let me know

OpenStudy (anonymous):

9x^2+16 so how would id o this one

OpenStudy (bahrom7893):

Well jim we already factored a couple of problems. Like see what i mean, tell them to use this formula: a^2-b^2 = (a-b)(a+b) Tell them to observe that: 4x2 - 9y2 = (2x)^2-(3y)^2, and tell them to do the substitution to factor.

OpenStudy (bahrom7893):

Sarsar I don't think that's factorable.

OpenStudy (bahrom7893):

Wait we can complete the square

jimthompson5910 (jim_thompson5910):

you can complete the square, but that won't make it factorable

OpenStudy (anonymous):

how do u know if something is not factorablw

OpenStudy (anonymous):

thi will be like this (3x+4)(3x-4)

OpenStudy (bahrom7893):

I think it can be factored

jimthompson5910 (jim_thompson5910):

if you have a sum of squares, then it is NOT factorable.

OpenStudy (anonymous):

whats a sum of squares

OpenStudy (bahrom7893):

9x^2+16 (3x)^2 + 2*3x*4 + 4^2 - 2*3x*4

OpenStudy (bahrom7893):

(3x+4)^2-24x

jimthompson5910 (jim_thompson5910):

a square is any expression that can be represented by squaring another expression. For example, 4 is a square of 2 since 2 squared = 4 Also, 4x^2 = (2x)^2 is another square

OpenStudy (anonymous):

ouch i am sorry i thought there is minuse so sorry!!!

OpenStudy (bahrom7893):

And then: (3x+4-sqrt(24x))(3x+4+sqrt(24x))

OpenStudy (bahrom7893):

I mean that just makes it uglier haha

jimthompson5910 (jim_thompson5910):

but when they say "factorable", they mean over the rationals.

jimthompson5910 (jim_thompson5910):

and you forgot the imaginary terms, which makes it even worse

OpenStudy (bahrom7893):

oh i guess, i mean i never learned how u guys do it here in the US.

OpenStudy (anonymous):

i kind of see it but not really ):

jimthompson5910 (jim_thompson5910):

don't worry about it, 9x^2+16 is NOT factorable

OpenStudy (anonymous):

how about this one 2xy-xz+2wy-wz

OpenStudy (bahrom7893):

Okay sarsar observe what is similar in the equation

OpenStudy (anonymous):

which would b the 2y?

OpenStudy (bahrom7893):

2xy-xz+2wy-wz 2xy+2wy-xz-wz 2y(x+w)-z(x+w)

OpenStudy (bahrom7893):

So: (x+w)(2y-z)

OpenStudy (anonymous):

i think u can do like this : 9x^2 +9+7 then we wil factor : 9(x^2+1)+7 then:( 9+7)(x^2+1)

OpenStudy (anonymous):

am i right?

OpenStudy (anonymous):

4ax + 8ay + 3bx + 6by so like in this one, do i start by taking out the GCF?

jimthompson5910 (jim_thompson5910):

sorry Roh, that's not the correct factorization. You can verify that by expanding

OpenStudy (bahrom7893):

no u pulled out 9+7, u can't do that

jimthompson5910 (jim_thompson5910):

first, group terms (4ax + 8ay) + (3bx + 6by)

jimthompson5910 (jim_thompson5910):

what comes next?

OpenStudy (anonymous):

mmmm yeah ur right bahroom

OpenStudy (bahrom7893):

Jim where did u get that one from?

jimthompson5910 (jim_thompson5910):

which one?

OpenStudy (bahrom7893):

oh u just took it as an example? I see was talkin about this (4ax + 8ay) + (3bx + 6by)

OpenStudy (anonymous):

ahhhhh im confused lol

OpenStudy (bahrom7893):

I think ima leave, having too much people to help confuses others

OpenStudy (bahrom7893):

*too many

OpenStudy (anonymous):

yoou can factor it by group factoring sarsar no confusing is needed let me do it

jimthompson5910 (jim_thompson5910):

4ax + 8ay + 3bx + 6by (4ax + 8ay) + (3bx + 6by) 4a(x + 2y) + 3b(x + 2y) (4a+3b)(x + 2y)

OpenStudy (anonymous):

4ax + 8ay + 3bx + 6by ok so u group the terms (4ax+8ay) (3bx+6by)

jimthompson5910 (jim_thompson5910):

first group the terms, then pull out the GCF from each group. From there, combine like terms.

OpenStudy (anonymous):

4a(x+2y)+3b(x+2y) (x+2y)(4a+3b)

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