Question

Simplify by removing factors of 1
q^2-49 over (q+7)^2

Answer 1

\[\left(\begin{matrix}q^2-49 \\ (q+7)^2\end{matrix}\right)\]

Answer 2

Btw, if you want do fractions bad, you can type frac{top}{bottom} to get:
\[\frac{top}{bottom}\]
Anyways, factor the top giving:
\[\frac{(q+7)(q-7)}{(q+7)^2}=\frac{q-7}{q+7}\]

Answer 3

ok so it's q-7/q+7? Sorry I don't understand algebra

Answer 4

Well you can "cancel" the common factor. In this case, q+7. So yes.

Answer 5

For example, if you had:
\[\frac{4}{2}=\frac{2*2}{2}=\frac{2}{1}=2\]
Its the same concept.

Answer 6

Oh ok I see it now! Thank you

Answer 7

No problem :P