Question

4. Find the probability that a randomly chosen point in the figures lies in the shaded region.

Answer 1

didnt we do this one already? mighta been yesterday ...

Answer 2

Hint: Find the area of the square and the area of the circle

Area of blue region = area of square - area of circle

Answer 3

then?

Answer 4

what are your results for it?

Answer 5

then area of blue region over area of entire figure = probability of landing in blue region

Answer 6

i dont know how but i got 72

Answer 7

what is the area of the square? its got sides of 12

Answer 8

i really dont know

Answer 9

Area of square = side * side

Area of square = 12*12

Area of square = 144 square units

Answer 10

ok so how I find area of this

Answer 11

jim explained how to find it .... how is it that you can be asking questions of this caliber and not know how to find the area of a square or a circle yet?

Answer 12

well it said 12 so I do 12*12 and i get 144 then it said find the area of circle but there is nothing inside it

Answer 13

ok ... we have to find the area of the circle in order to subtract that value to find the shaded parts :)

Answer 14

the radius of the circle is going to be half of a side of the square; or 6

Answer 15

Notice how the sides of the square are tangent to the circle. So this suggests that


side of square = diameter of circle

Answer 16

so it is 12-6?

Answer 17

the area of a circle is found by the rote formula of pi r^2

in this case r = 12/2

Answer 18

so 452.16

Answer 19

You forgot to divide 12 by 2 to get 6 for the radius

Answer 20

144 - 36pi
---------- is what you should end up with eventually
144

Answer 21

so 452.16

Answer 22

but how did you get 36

Answer 23

Area of circle: \[A=\pi r^2 = \pi(6)^2 = 36\pi\]

Answer 24

so 452.16

Answer 25

ok so i finally got 143.75

Answer 26

probability tends to be expressed as a value between 1 and 0

Answer 27

so 452.16

Answer 28

ok so what do i do with 143.75

Answer 29

id throw it out since I get abt .215 as an answer