Question

sqrt x + 33 plus sqrt x - 2 =7

Answer 1

I take it you need to solve for x?

Answer 2

yes

Answer 3

Organize your work with parentheses first.

Answer 4

What do you mean?

Answer 5

Erm, its hard to see what your trying to say, because is it \[\sqrt{x} - 2 \] or \[\sqrt{x-2}\] They're two different values, by the way.

Answer 6

Considering you mean \[\sqrt{x+33}+\sqrt{x-2}=7\]
You multiply by \[\sqrt{x+33}-\sqrt{x-2}\]
And you get
\[(x+33)-(x-2)=35=7(\sqrt{x+33}-\sqrt{x-2})\leftarrow \rightarrow \sqrt{x+33}-\sqrt{x-2}=5\]

So you have a system
\[\sqrt{x+33}+\sqrt{x-2}=7 \]
\[\sqrt{x+33}-\sqrt{x-2}=5\]

You add them up and get
\[2\sqrt{x+33}=12\]
\[\sqrt{x+33}=6\]
Meaning
\[x+33=36\leftarrow \rightarrow x=3\]

Answer 7

Let's say its

(sqrt x + 33) + (sqrt x - 2) =7

Answer 8

Oh, u did already...

Answer 9

Yep I did hehe

Answer 10

Wolfram agrees with u

http://www.wolframalpha.com/input/?i=sqrt+%28x+%2B+33%29+%2B+sqrt+%28x+-+2%29+%3D7