Mathematics
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OpenStudy (anonymous):
find the missing coordinate......20x + 3y=27 (1/2,y)
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OpenStudy (anonymous):
x=1/2, put that value in, see what happens.
OpenStudy (anonymous):
so 20 * 1/2 =10
OpenStudy (anonymous):
right, so we get 10+3y=27
OpenStudy (anonymous):
so 1/2 represents y also
OpenStudy (anonymous):
No, you need to solve 10+3y=27 to get y.
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OpenStudy (anonymous):
ok you put a multiple with 3 to get your answer?
OpenStudy (anonymous):
ehh, what? Do you know how to solve 10+3y=27?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Let's do it together.
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
first we need to get the 10 on the other side, how do we do that?
OpenStudy (anonymous):
10+3(10)
OpenStudy (anonymous):
I'm afraid not, subtract 10 from both sides of the equation.
OpenStudy (anonymous):
(10-10)+ (3-10)
OpenStudy (anonymous):
10 - 3y is one side of the equation, 27 is the other.
So when we substract 10 from both sides we get 10-3y-10=27-10
Right?
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so what does 10-3y-10 equal?
OpenStudy (anonymous):
?????
OpenStudy (anonymous):
10-3y-10=10-10-3y=?
OpenStudy (anonymous):
-3
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OpenStudy (anonymous):
are you sure?
OpenStudy (anonymous):
10-3y-10= -3y and 10-10-3y=-3y...... so what am I doing wrong
OpenStudy (anonymous):
right -3y
OpenStudy (anonymous):
-3y=27-10
OpenStudy (anonymous):
27-10=17 so the equation we get is -3y=17 right?
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OpenStudy (anonymous):
;~)
OpenStudy (anonymous):
we're almost there, how do we get to y=... ?
OpenStudy (anonymous):
wow i'm going to fail my test I thought we were done
OpenStudy (anonymous):
You're done when you get to y=... now we have -3y=17
OpenStudy (anonymous):
You need to divide both sides of the equation by -3 to get to y=...
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OpenStudy (anonymous):
what does the left side of the equation become if we divide by -3?
OpenStudy (anonymous):
if i'm dividing -3 into -3????
OpenStudy (anonymous):
you divide -3y by -3
OpenStudy (anonymous):
-y
OpenStudy (anonymous):
what's \[\frac{-1}{-1}\]?
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OpenStudy (anonymous):
i can't figuire it out
OpenStudy (anonymous):
\[\frac{-1}{-1}=1\]
if you divide a negetive number by a negative number you get a positive number.
OpenStudy (anonymous):
so what's \[\frac{-3y}{-3}\]
OpenStudy (anonymous):
6y
OpenStudy (anonymous):
\[\frac{2}{2}=1, \frac{-1}{-1}=1, \frac{-3}{-3}=1\]
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OpenStudy (anonymous):
\[\frac{-3y}{-3}=\frac{-3}{-3}y\]
OpenStudy (anonymous):
So \[\frac{-3y}{-3}=y\] right?
OpenStudy (anonymous):
??????
OpenStudy (anonymous):
what is 2y/2?
OpenStudy (anonymous):
are they both positive
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OpenStudy (anonymous):
yes, there are no minus signs.
OpenStudy (anonymous):
y is the answer
OpenStudy (anonymous):
right
OpenStudy (anonymous):
so what's -3y/-3
OpenStudy (anonymous):
y
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OpenStudy (anonymous):
that's right
OpenStudy (anonymous):
that's one side of the equation
OpenStudy (anonymous):
now the other 17/-3
OpenStudy (anonymous):
i have just lost the whole purpose of the equation
OpenStudy (anonymous):
We started out with 20x+3y=27, x was 1/2 and to find y we had to solve the equation 20*1/2 +3y=27
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OpenStudy (anonymous):
which makes me see that we made a mistake.
OpenStudy (anonymous):
we had -3y, but it has to be 3y
OpenStudy (anonymous):
can you write it in long form
OpenStudy (anonymous):
You mean \[\frac{a}{b}\]
what do you want me to write?
OpenStudy (anonymous):
this is very long I have to put this on the back burning and move to the next problem
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OpenStudy (anonymous):
Well y=17/3 for you information.
OpenStudy (anonymous):
thank you for your help
OpenStudy (anonymous):
You're welcome.