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√6 over √3+5
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\[\left(\begin{matrix}\sqrt{6} \\ \sqrt{3}+5\end{matrix}\right)\]
I'd start by multiplying top and bottom by the conjugate of \(\sqrt{3} + 5\)
But otherwise this doesn't simplify much.
0.363855
\[\sqrt{70}*\sqrt{169}\]
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we solved this for you
no
12 sq(70)
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