Question

Please help! Find the following infinite sum, if its exists. If one does not exist enter "no infinite sum."
(Look at response.)

Answer 1

\[\sum_{n-1}^{\infty}4(1/3)^(n-1)\]

Answer 2

n-1 is raised (^)

Answer 3

\[4\sum _{n=1}^{\infty } \left(\frac{1}{3}\right)^{n-1}\]

Answer 4

I am going to change it

Answer 5

\[4\sum _{n=0}^{\infty } \left(\frac{1}{3}\right)^n\]

Answer 6

That's correct :/ Sorry

Answer 7

This is formula
\[\sum _{n=0}^{\infty } a^n =\text{ }\frac{1}{1-r}\]

\[\sum _{n=0}^{\infty } (1/3)^n =\text{ }\frac{1}{1-(1/3)}\]

Answer 8

1/(2/3)
3/2

Answer 9

So the infinite sum would be 3/2?

Answer 10

yes, by the way we were able to do it because 1/3 is less than 1

Answer 11

times 4

Answer 12

Huh Zarkon?

Answer 13

3/2*4=6

Answer 14

oh yeah , we forgot about 4 infront

Answer 15

Oh I see. So final answer= 6. Thank you guys! :)