Hi I need help understanding how to do my problems..if I can understand one I can get the rest. Consider the following hypothesis test: Ho: U > 20 Ha: U < 20 A sample of 50 provided a sample mean of 19.4 - population standard dev. is 2. Compute the value of the test statistic. What is the p-value and using alpha .05 what is my conclusion?
Ho is spose to be an equality; perhaps H0=20 Ha should represent either what the claim is; or NOT the claim depending on how the claim is worded. im gonna assume this to be: Ho=20 Ha<20 ; this gives us a left tailed test since the sign is pointing left. There tends to be a flow chart on how to determine which test statistic is used, if i recall correctly we have: If the parameter is the mean; and the distribution is normal; and the sample size (n) > 30, and a known "o~" we can use the Z score as out test statistic the z-score equates to: (given statistic - claim)/(modified sd), in this case I would say: (19.4 - 20) Z= ---------- = -.3 sqrt(50) = abt. -2.121... 2 /sqrt(50)
since this is our threshold; anything falling to the left of it will cause us to reject Ho; and anything to the right of it will cause us to "fail to reject" Ho. The p-value is simply determined by finding the cumulative area (probability) from -inf to -2.121 under the distribution curve; keep in mind that i am assuming this to be a normal distribution. We can use a z-table to determine the area; look at the column on the left and find 2.1 ; then match that up with the top row that matches .02: 2.12-------------.02 . | . | . | 2.1 ------------- (N) ^ this number, in my book at least, gives the area between the mean and the z-score In order to use out N value we have to adjust it to find the area NOT between the mean and the z-score. Lets do this; .5 is all the area up to the mean; so add our N to it .5 + N = all the area that is NOT what we want so subtract that from 1 (the entire area under the curve equals 1) 1 - (.5+N) is our p-value; to which i get .0170
we compare this to the value of our significance level; that "alpha" value of .05 if our p-value is greater than alpha; we "fail to reject" Ho if our p-value is less than alpha; we "reject" Ho. .0170 is LESS THAN .05; so we "REJECT" the null hypothesis, Ho
if you have the ti83 or equivalent; its easier to determine :) stat--tests--1:(Z-test)-- enter in values Uo: 20 o~: 2 \(\bar x\): 19.4 n: 50 U: <Uo Calculate .............................................. output is: z = -2.121.... p-value = .01694... comapre p-value to alpha and determine your conclusion
think of it as the z-score tells us how far we are away from the mean; and the alpha sets a boundary; if out z-score is to far away from the mean it goes out of bounds. alpha boundary <.....|...............||.................................|||.................................> mean |<----------------------------| z-score
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