Question

solve f(x)+g(x)=6
f(x) = log2(x-7) and g(x) = log2(3x-5)
my only answers choices are
a) 9
b) -9
c) 512
d) -512

Answer 1

do this 2 refer to base

Answer 2

most likely, yes :)

Answer 3

yes the 2 is the base

Answer 4

Since the bases of logarithms are matching, we'll apply product rule:
log2[(x-7)(3x-5)] = 6
We'll take antilogarithm:
[(x-7)(3x-5)] = 2^6
We'll remove brackets:
3x^2 - 26x + 35 = 64
3x^2 - 26x + 35 - 64 = 0

Answer 5

3x^2 - 26x - 29 = 0
x1 = [26+sqrt(676 +348 )]/6
x1 = (26+32)/6
x1 = 58/6
x1 = 29/3

Answer 6

x2=-1

Answer 7

29/3 and -1 are not in the proposed answers...

Answer 8

there are not correct

Answer 9

that would explay why i can't find the reight answer to the other question of jaersonandres...

Answer 10

that would be my teachers fault for putting incorrect answers... thats why i got stuck and asked

Answer 11

that's crazy that your teacher got wrong in two questions