Tina wants to save money for school. Tina invests $1000 in an account that pays an interest rate of 8%. How many years will it take for the account to reach $1300? Round your answer to the nearest hundredth.
do we assume a compounded rate of once a year?
I guess.
A=P(r+1)^t
if so, then: 1300 = 1000 (1+.08)^t ; divide out the 1000 1300/1000 = (1.08)^t ; now ln it all ln(13/10) = ln[(1.08)^t] ; apply log rules ln(13/10) = t * ln(1.08) ; and divide out the ln(1.08) ln(13/10)/ln(1.08) = t
So it's 1.08..?
dunno; the calculator has to figure that out ....
google has a nice calculator feature; just type it in the search box and it should just pop out an answer
Type in ln(13/10)/ln(1.08) = t ?
http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=ln(13%2F10)%2Fln(1.08)
not the "=t" part :)
Ok thanks.
to dbl chk the results; insert the value you get for "t" into the original equation
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