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I am trying to get the integral
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I am writingit now
\[\int\limits_{2}^{4} \left(\begin{matrix}dx \\ /x(lnx)^2\end{matrix}\right)\]
that slash means division
Let u = ln x, du = dx/x, and substitute into the original integral to reduce it to something more recognizable.
so, let = 1nx, okay let me try that, cause i have been letting u = (lnx)^2 and its been a nightmare
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I think that plain ln x for u will be munc less of a nightmare.
so in did that and got so far u^-1/-1
That's the same as\[-\int\limits_{}^{}du/u.\]
Familiar?
yup
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Get it back to original x and you're done.
i am still stuck at this part: \[\int\limits_{2}^{4} du/u^2\]
i got it
Power formula. Rewrite as\[\int\limits_{}^{}u^{-2}du\]
:^)
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