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Mathematics 8 Online
OpenStudy (anonymous):

I am trying to get the integral

OpenStudy (anonymous):

I am writingit now

OpenStudy (anonymous):

\[\int\limits_{2}^{4} \left(\begin{matrix}dx \\ /x(lnx)^2\end{matrix}\right)\]

OpenStudy (anonymous):

that slash means division

OpenStudy (anonymous):

Let u = ln x, du = dx/x, and substitute into the original integral to reduce it to something more recognizable.

OpenStudy (anonymous):

so, let = 1nx, okay let me try that, cause i have been letting u = (lnx)^2 and its been a nightmare

OpenStudy (anonymous):

I think that plain ln x for u will be munc less of a nightmare.

OpenStudy (anonymous):

so in did that and got so far u^-1/-1

OpenStudy (anonymous):

That's the same as\[-\int\limits_{}^{}du/u.\]

OpenStudy (anonymous):

Familiar?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Get it back to original x and you're done.

OpenStudy (anonymous):

i am still stuck at this part: \[\int\limits_{2}^{4} du/u^2\]

OpenStudy (anonymous):

i got it

OpenStudy (anonymous):

Power formula. Rewrite as\[\int\limits_{}^{}u^{-2}du\]

OpenStudy (anonymous):

:^)

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