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How to find the minimum value of sinX + cosX?
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Take the derivative of y, set it equal to zero, then solve for x
i.e cosX -sinX = 0
cosXsinX = 1/2
How to proceed further?
wait a sec
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Okay, I will provide the full solution here
0 = cosx - sinx sinx = cosx sin x/cos x = 1 tan x = 1 x = tan^-1(1) x = 45 I suppose that would be the minimum value
Unless you're supposed to add 180 to that and get 225
That would put x in the third quadrant which would be negative
exactly...!
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Okay :)
thanks buddy!!!!
You're welcome
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