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Mathematics 9 Online
OpenStudy (anonymous):

How to find the minimum value of sinX + cosX?

hero (hero):

Take the derivative of y, set it equal to zero, then solve for x

OpenStudy (anonymous):

i.e cosX -sinX = 0

OpenStudy (anonymous):

cosXsinX = 1/2

OpenStudy (anonymous):

How to proceed further?

hero (hero):

wait a sec

hero (hero):

Okay, I will provide the full solution here

hero (hero):

0 = cosx - sinx sinx = cosx sin x/cos x = 1 tan x = 1 x = tan^-1(1) x = 45 I suppose that would be the minimum value

hero (hero):

Unless you're supposed to add 180 to that and get 225

hero (hero):

That would put x in the third quadrant which would be negative

OpenStudy (anonymous):

exactly...!

hero (hero):

Okay :)

OpenStudy (anonymous):

thanks buddy!!!!

hero (hero):

You're welcome

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