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Solve for Y -2ln |y| + ln |2y-9| + ln|2y+9| = 162X + C
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C is just an integration constant.
Recall that the sum of logs is the log of a product: \[-2(ln\ y) + ln(2y-9) + ln(2y+9)\]\[=ln(\frac{4y^2 - 81}{y^2})\]\[\implies ln(\frac{4y^2 - 81}{y^2}) = 162x + C\]\[\implies 4 - \frac{81}{y^2} = Ce^{162x}\]
And continue from there to solve for y.
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