perform the indicated operation: 5/2x+3y ÷ 10/ 4x^2-9y^2

Question

anonymous · Answer

Is it

    5                                   10
------- divided by   ----------
 2x+3y                        4x^2-9y^2

or

  5                                    10
---- + 3y  divided by  ------  -  9y^2
  2x                                 4x^2

anonymous · Answer

the first one.

anonymous · Answer

$$=(\frac{5}{2x+3y})(\frac{4x^2-9y^2}{10})$$This becomes:$$(\frac{1}{2x+3y})(\frac{(2x+3y)(2x-3y)}{5})$$Cancel common factor of 2x+3y:$$\frac{2x-3y}{5}$$

anonymous · Answer

5                                   10
------- divided by   ----------
 2x+3y                        4x^2-9y^2

   5                   4x^2-9y^2
-------  *     -----------
 2x+3y                   10

  5 [(2x)² - (3y)²]          5 [(2x + 3y) (2x - 3y)]              2x - 3y
---------------  =  ---------------------   = -----------
 10 (2x + 3y)                        10 (2x + 3y)                           2

anonymous · Answer

eseidi has made a slight mistake.....

anonymous · Answer

oooops...yeah the denominator is 2 not 5 as I said lol sorry