Mathematics
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OpenStudy (anonymous):
\[4\sqrt{X^12}\] / \[24\sqrt{X^2}\]
its a fraction and in the first sqrt its x^12
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OpenStudy (anonymous):
sqrt = power 1/2
OpenStudy (anonymous):
LOL, nearly....
OpenStudy (anonymous):
Use \frac{}{} for a fraction
OpenStudy (anonymous):
4(x^6)/24x= x^6/6x=x^5/6
OpenStudy (anonymous):
is that the answer misterchyme?
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OpenStudy (anonymous):
(x^5)/6 yes
OpenStudy (anonymous):
(x^5)/6 is the answer?
OpenStudy (anonymous):
\[\sqrt[4]{x^{12}}=x^3\]
OpenStudy (anonymous):
Though he said sqrt..
OpenStudy (anonymous):
thats the solution for the first one
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OpenStudy (anonymous):
Oh, not square root, fourth root.
OpenStudy (anonymous):
So next one is 24th root?
OpenStudy (anonymous):
oh i thought it was 4 times the sqrt
OpenStudy (anonymous):
i mean im supposed to have a simplification for the whole thing
OpenStudy (anonymous):
its a fraction
the roots are on top of eachother
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OpenStudy (anonymous):
\[\sqrt[24]{x^2}=\sqrt[12]{x}\]
OpenStudy (anonymous):
ok sorry. i guess i am lost.
OpenStudy (anonymous):
thank you guys for the help, its confusing
OpenStudy (anonymous):
ill send a file attached so you can see it
OpenStudy (anonymous):
In English it's the fourth root of x power 12 divided by 24th root of x squared, is that right?
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OpenStudy (anonymous):
OpenStudy (anonymous):
i have no idea estudier
OpenStudy (anonymous):
Look like constants to me
OpenStudy (anonymous):
see i was right! lol
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OpenStudy (anonymous):
ohh hahha so whats the answer misterchyme?
OpenStudy (anonymous):
(x^5)/6 final answer
OpenStudy (anonymous):
thanks can you help me with more misterchyme?
OpenStudy (anonymous):
\[\dfrac{4 \sqrt {x^{12}}} {24 \sqrt{x^2}}\]
OpenStudy (anonymous):
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OpenStudy (anonymous):
Post it as a new question, it will just confuse everyone to put it here..
OpenStudy (deoxna):
\[\sqrt{x^{10}}/6\]
OpenStudy (anonymous):
deox is that the final answer?
OpenStudy (anonymous):
estudier i would if i knew how to attach it to make a new question
im new at this
OpenStudy (anonymous):
30x^8sqrt2/5x^2sqrt2
6x^6... i think
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OpenStudy (anonymous):
:/ can you help me with this?
OpenStudy (anonymous):
10x^2