Question

y = ln(5x^3 – 2e^2x + 1)^4 find the derivative

dont know how to set up the rule for this derivative

Answer 1

thats too long O.O
\[y = \ln(junk) \Rightarrow y' = \frac{1}{junk}*(junk)'\]

Answer 2

\[y=\ln[g(x)]^4=4\ln[g(x)] => y'=4*\frac{g'(x)}{g(x)}\]

Answer 3

g(x)....junk....same stuff lol

Answer 4

lol

Answer 5

g(x)=junk^4

Answer 6

joe the first part of your setup is all needed?

Answer 7

wait g(x) didn't include 4

Answer 8

lol

Answer 9

myininaya's formula is good, i would use hers. to turn that annoying power into something thats not very annoying at all.

Answer 10

but joe's formula is good because its all you really need to know to do these

Answer 11

joe's is more general than mine

Answer 12

now i am confused but thank you both

Answer 13

lol >.< sry sry

Answer 14

lol
they are basically the same
i just have a contant times (junk)'/junk

Answer 15

where my junk almost equal's joe's junk

Answer 16

lol
ok i will stop

Answer 17

hahahaha

Answer 18

i wish i could give more medals lol

Answer 19

yep