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If $2,500 is invested with an interest rate of 10%, compounded continuously, determine the amount of money in the account after 5 years.
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Let \[f(t)=f _{0}*e ^{0.10t},f _{0}=f(0)=2500$ \] be the function that determines the amount of money in t years thus, with t=5 years \[f(5)=2500*e ^{0.5}\approx 4121,80\]
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