Question

what is 3^n+4 = 27^2n

Answer 1

im trying to solve for x by determining
the common base

Answer 2

then itd be (3^n)+4=3^6n

Answer 3

27 is 3^3
so 27^2n is 3^6n then its just n+4=6n

Answer 4

n=4/5

Answer 5

wait is it 3^(n+4) or 3^n + 4

Answer 6

i want to find the common base,

Answer 7

I assumed it was 3^n+4

Answer 8

ya thats just a much harder problem depends on what math class this is for

Answer 9

if the problem is like 3^(n+4) then it can be easily solved if its like 3^n+4 then it'd be done by log properties.

Answer 10

exactly

Answer 11

im looking for n

Answer 12

could you please correctly state the problem using paranthesis if necessary.

Answer 13

its either 4/5 or .8ln(1/3)

Answer 14

depending on if the problem does or does not have parenthesis respectively

Answer 15

solve for x by determind a common base showing all your work : 3^n+4 = 27^2n

Answer 16

if you would like help could you please attach the paper that has the problem on it for us to analyze what is the correct way the problem is written?

Answer 17

is the problem:
\[3^{n+4} \]
or
\[3^n+4\]

Answer 18

the first one joe

Answer 19

ok, so we have:
\[3^{n+4} = 27^{2n}\]
using the fact that:
\[27 = 3^3\]
we can rewrite the equation as:
\[3^{n+4} =3^{3(2n)} \Rightarrow 3^{n+4} = 3^{6n} \]
therefore:
\[n+4 = 6n \Rightarrow 5n = 4 \Rightarrow n = \frac{4}{5}\]

Answer 20

and the common base is 3...so your answer is 3^(n+4)=3^(6n) where n=4/5 by solving n+4=6n

Answer 21

THANK YOU SO MUCH JOE & MATRIXX !!

Answer 22

your welcome :)