Question

Given two spheres, if the volume of the first sphere is 4/3*3.14 and the volume of the second sphere is 36*3.14 , which is the relation of the second radius to the first?
squared
tripled
doubled
multiplied by a factor of 8/3

Answer 1

\[\frac{4}{3}pi r^3 = \frac{4}{3}\pi\]

So for this first sphere, r must be equal to 1.

\[\frac{4}{3}\pi r^3 = 36\pi\]

You need to solve this second equation for r.

Cancel out the pi and Multiply both sides by (3/4) to get
\[r^3 = 27\]
\[r = \sqrt[3]{27} = \sqrt[3]{3^3} = 3\]

r = 3 for the second sphere.

The second radius is triple the first radius.