Question

Pleaseeeee helppp meeee :( Which is correct about the inflection point for the function f(x)= e^x - 2x^2 inflection point is at x=0 '' '' '' is at x=1.39 '' '' '' is at x=1.5 '' '' '' is at x=1.69

Answer 1

You don't have a graphing calculator?

Answer 2

no:(

Answer 3

you need to take the second derivative first, that would be:
\[f(x) = e^x-2x^2 \Rightarrow f'(x) = e^x-4x \Rightarrow f''(x)=e^x-4\]
Setting the second derivative equal to zero we obtain:
\[0 = e^x-4 \Rightarrow e^x = 4 \Rightarrow x = \ln(4)\]
According to wolfram alpha, ln(4) = 1.386

Answer 4

You are amazing!!!