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Mathematics 16 Online
OpenStudy (anonymous):

how do you if this series converges or diverges.

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty} n/(n+1)2^n\]

OpenStudy (anonymous):

there are many test which you can perform 1) Divergence Test 2) Integral Test 3) Ratio Test 4) Limit Comparison Test others which I don't remember

OpenStudy (anonymous):

no 2^n is also in the denominator

OpenStudy (anonymous):

\[\sum _{n=1}^{\infty } \frac{n}{(n+1)2^n}\] 1) Divergence Test is inconclusive 2)By ratio test \[\frac{n+1}{(n+2)2^{n+1}}*\frac{(n+1)2^n}{n}\] \[\frac{2^n}{2^{n+1}}\frac{(n+1)^2}{n(n+2)}\] we get 1/2 which is less than 1 , so series converge by ratio test

OpenStudy (anonymous):

Let me know, if you need more clarification above

OpenStudy (anonymous):

i understand! thank you!

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