Question

please help!

Answer 1

\[\left[\begin{matrix}a & b \-\ b & a\end{matrix}\right]\left(\begin{matrix}a- a ^{2} \\ a+b\end{matrix}\right)\]

Answer 2

the way thats written is kinda confusing...

Answer 3

a-a^2 divided by a+b?

Answer 4

times ab/-ab?

Answer 5

yeah!

Answer 6

ab/-ab
whats that?

Answer 7

no its a/b-b/a

Answer 8

oh i see
so then you find a common denominator which in this case would be ab

Answer 9

then solve that

Answer 10

what do you get?

Answer 11

i dont kno how to solve it

Answer 12

a/b-b/a
the common denominator is ab
so multiplay a/b by a and multiply b/a by b
a^2/ab -b^2/ab
(a^2-b^2)/ab
then that can be factored as the difference of two squares
(a-b)(a+b)

Answer 13

then wahts the second part of the problem?
(a-a^2)/a-b?

Answer 14

(a-a^2)/(a-b)

Answer 15

(a-a^2/a+b)

Answer 16

well in the numerator you can factor out an a. a(1-a) and the denominator we can cancel out since the numerator of the other problem contains a+b

so with that we have
[(a-b)/ab][a(1-a)]

Answer 17

we can cancel out the a in the numerator and denominator
a-b/b times 1-a

Answer 18

okay

Answer 19

is that the final answer?

Answer 20

multiply it out and post what you get

Answer 21

umm -ab?

Answer 22

a-a^2-b-a/ab
a^2-b/ab

Answer 23

okay thanks!