Question

someone please help

Which of the following describes the non-rigid transformation in the function shown below? y-1=-(3x+1)^2


A. The graph is stretched horizontally to 1/3 the original width
B. The graph is stretched vertically by a factor of 3.
C. The graph is shifted 3 units down.
D. The graph is reflected across the x-axis.

Answer 1

What can you tell me about transformations?

Answer 2

i dont really know anything about them, thats why i need help

Answer 3

Ok well then lets start with the basics and work our way up.

Answer 4

That work?

Answer 5

No?

Answer 6

sure

Answer 7

Sorry, Didn't see you reply to this. Are you still interested in working through transformations?

Answer 8

yes

Answer 9

We start by looking at something with no transformation at all:

y = x^2

Then we compare it to a transformation:

y = x^2 + 1

How will the y values differ from the first version of the function for a given value of x?

Answer 10

moved to the left 1??

Answer 11

Nope. If I plug in a 0 for x in the first one, I get y = 0, But if I plug in a 0 for x in the second one I get y = 1.

So the graph has been shifted up 1 unit for the same value of x.

Answer 12

ok

Answer 13

And if we re-write it as:

y - 1 = x^2

It's still the same thing. A parabola shifted up one unit. So now the vertex is at (0,1) instead of (0,0).

Answer 14

Now if we see that x = (x-0)

We can also re-write it as:

y - 1 = (x-0)^2

Answer 15

which you know from your other problem is an easy way to find the vertex (0,1)

Answer 16

so in the problem, were looking at the -(3x) part of the problem, right?

Answer 17

We will do that part now yeah.

Answer 18

So it's -(3x+1)

Answer 19

so wats the transformation for -(3x+1)