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OpenStudy (anonymous):
x ^{sqrt{logx}}=10^{8}
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OpenStudy (anonymous):
\[x ^{\sqrt{logx}}=10^{8}\]
OpenStudy (anonymous):
how does 8log10 = 8?
OpenStudy (anonymous):
what are we doing here? just solving for x?
OpenStudy (anonymous):
yeah without using a calculator
OpenStudy (anonymous):
that is because log (10) = 1, when there is no base, its understood to be base 10
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OpenStudy (anonymous):
but ten wasn't the base
OpenStudy (anonymous):
then what is the base? you gotta put it or else people will think its 10
OpenStudy (anonymous):
ok sorry let me show you where i got to
OpenStudy (anonymous):
\[\left( \sqrt{logx} \right)\left( logx \right)=10^{8}\]
OpenStudy (anonymous):
\[=8\log10\]
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OpenStudy (anonymous):
Right. So you are taking the log (base 10) of both sides of the equation. the right hand side simplifies to 8
OpenStudy (anonymous):
So you should have:
\[\sqrt{\log(x)}*\log(x) = 8\]
OpenStudy (anonymous):
does it simplify because since the logs base is ten and since its \[8log _{10}10\] thelog simplifies to 1?
OpenStudy (anonymous):
Right :)
OpenStudy (anonymous):
ohhhh thanks see i knew the base of log was ten but i didnt know that i could do that thanks!!
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OpenStudy (anonymous):
So do you have an idea of where to go from here?
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
cool, have fun :)
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