x ^{sqrt{logx}}=10^{8}
\[x ^{\sqrt{logx}}=10^{8}\]
how does 8log10 = 8?
what are we doing here? just solving for x?
yeah without using a calculator
that is because log (10) = 1, when there is no base, its understood to be base 10
but ten wasn't the base
then what is the base? you gotta put it or else people will think its 10
ok sorry let me show you where i got to
\[\left( \sqrt{logx} \right)\left( logx \right)=10^{8}\]
\[=8\log10\]
Right. So you are taking the log (base 10) of both sides of the equation. the right hand side simplifies to 8
So you should have: \[\sqrt{\log(x)}*\log(x) = 8\]
does it simplify because since the logs base is ten and since its \[8log _{10}10\] thelog simplifies to 1?
Right :)
ohhhh thanks see i knew the base of log was ten but i didnt know that i could do that thanks!!
So do you have an idea of where to go from here?
yes!
cool, have fun :)
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