Find the solution to the system of equations represented by the matrix shown below. 3 -1 7|53 1 7 1|61 9 1 1|67 A.x = 6, y = 21, z = 54 B.x = 6, y = 7, z = 6 C.x = 42, y = 7, z = 6 D.x = 54, y = 21, z = 54
Are you just checking answers, or are you not sure how to find it?
Both.
Well how can you check your answer and not know how to do it? You'd have no answer to check ;p
You don't know how to use gauss-jordan elimination to write a matrix in reduced row echelon form to retrieve the solution to a system of linear equations? You can try plugging in values from each multiple choice answer until they fit.
True, you could find it by process of elimination certainly.
I was never taught how to do it. Its part of a test im taking..
That sucks :-( Lets teach you :-D there are video tutorials out there I'll link one to you or I can type the algorithm here.
Okaay, thank you so much!
ughh. this is so confusing :(
This matrix is a little difficult to do by hand. if you see hard matrices like this in multiple choice you should probably guess it to get choice b (by trying all answers to see if they work). It is faster than elimination To eliminate matrices you follow basic steps to eliminate each column: 1. switch a row containing a leading '1' into the top 2. perform row operations (multiplying row 1 and subtracting row 1 from the values in the other rows) to make all the other elements in the first column 0 3. switch columns and do the same steps but for the second row to have a leading 1 for this particular matrix you can follow these steps: Eliminating the first column 1. switch rows 2 and 1 (so the top row reads 1 7 1 61) 2. multiply row 1 by 3 and subtract row 2 by row 1 (so row 2 reads 0 -22 4 -98) 3. multiply row 1 by 9 and subtract row 3 by row 1 (so row 3 reads 0 -62 -8 -410) now you have a matrix that reads [ 1 7 1 | 61 ] [ 0 -22 4 | -98 ] [ 0 -62 -8| -410] next step is to do something like divide row 2 by -22, and then subtract it from row 3 (after multiplying by -62). you should finally get something like 1 0 0 6 0 1 0 7 0 0 1 6 in the end
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