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Mathematics 25 Online
OpenStudy (unknown):

which of the binomials below is a factor of this trinomial? x^2+3x-10 a)x^3+5 b)x-5 c)x+2 d)x+5

OpenStudy (anonymous):

d) is a factor of x^2+3x-10

OpenStudy (unknown):

thanks! what about: x^2+4x-32 a)x+4 b)x^2+8 c)x-4 d)x-8

OpenStudy (anonymous):

\[x^2+4 x-32=(x-4) (x+8) \]

OpenStudy (unknown):

whattt

OpenStudy (anonymous):

c) x-4

OpenStudy (unknown):

hah you went like Japanese on me! so how about this one: x^2+6x+8 a)x^2+4 b)x+4 c)x-4 d)x+8

OpenStudy (unknown):

i got b

OpenStudy (anonymous):

b) x+4

OpenStudy (unknown):

woo. this next one is like confusing to me x^2+7x-60 a)x-12 b)x^2-5 c)x+12 d)x+5

OpenStudy (unknown):

and i got.. ohhh c is my guess?

OpenStudy (anonymous):

c) x+12

OpenStudy (anonymous):

The factors are x+12, and x-5. I am using Mathematica to factor these expressions.

OpenStudy (unknown):

haha alright. so what about this: factor the polynomial x^2+5x-24

OpenStudy (anonymous):

(x-3) (x+8)

OpenStudy (unknown):

is that considered descending order? jw

OpenStudy (unknown):

eh probs. alright next.: x^2+19x+84 a)x-7 b)x^2+12 c)x+84 d)x+7

OpenStudy (anonymous):

d) x+7

OpenStudy (anonymous):

Do you have many more expressions? If so list them together, separated by commas.

OpenStudy (unknown):

i have like five more. maybe but i can't see them all until i go from one question to the next.

OpenStudy (unknown):

okay so i have just factor x^2-x-6

OpenStudy (anonymous):

All I need is the binomial. You will receive the factors. You can then go back on your own to determine the x) type answer.

OpenStudy (unknown):

...

OpenStudy (anonymous):

\[x^2-x-6\to (x-3) (x+2) \]

OpenStudy (unknown):

x^2+3x-28 a)x+7 b)x^2+7 c)x+4 d)x-7

OpenStudy (anonymous):

\[ 4 x^6-x^3+x-3\to (x-4) (x+7)\]a) x+7

OpenStudy (unknown):

x^2+4x-12

OpenStudy (anonymous):

Oops. The expression to the left of the arrow should have been typed in as:\[x^2+3 x-28 \]

OpenStudy (anonymous):

\[x^2+4 x-12\to (x-2) (x+6) \]

OpenStudy (unknown):

it's cool. uhm x^2-5x+6

OpenStudy (anonymous):

\[x^2-5 x+6->(x-3) (x-2) \]

OpenStudy (unknown):

dude i got 100% :)

OpenStudy (unknown):

can you factor trinomials?

OpenStudy (anonymous):

yes

OpenStudy (unknown):

okay x^2-12x+35

OpenStudy (unknown):

it says factor the trinomial and enter the factorization below so i think that's that same thingg we've been doing

OpenStudy (anonymous):

just post the expression.

OpenStudy (unknown):

the one i just posted is the expression. ;p

OpenStudy (anonymous):

nothing is coming through. A polynomial should look like this: x^3 - 12 x^2 + 35 x - 12

OpenStudy (anonymous):

A trinomial that is.

OpenStudy (unknown):

that's what it says though. it only has three parts just like we were doing. so possibly it's the same thing

OpenStudy (anonymous):

you were doing fine with the binomials to be factored. you have yet to post a trinomial which looks like a binomial except one of the x unknown is raised to the third power.\[x^3 \]

OpenStudy (unknown):

no i know what it is. but this problem just gave me that. so i guess i'll just keep doing the same thing and hope for the best. it won;t lemme copy and paste.. so i just have to keep typing them.. grr

OpenStudy (unknown):

...

OpenStudy (tester97):

@tonystark1 this might help you?

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