Someone check my answer please? (typing in equation...)

Question

anonymous · Answer

$$(x+4)/(-x-3) > 0 $$

anonymous · Answer

erm nevermind.. was trying to make it pretty.. but is the answer $$x<-4\cup x>-3$$ ?

hero · Answer

wait a sec...let me re-post what you have

hero · Answer

Okay, I get it...wait

anonymous · Answer

Ok.. where it gets me is it says answer in interval notation o_O I get x<-4 or x>-3

dumbcow · Answer

well if you try x=0 you get -4/3 which is not positive

hero · Answer

dumbcow, x = 0 is not even a possible solution

anonymous · Answer

I'm becoming more confused haha

hero · Answer

Why?

dumbcow · Answer

$$\frac{x+4}{-x-3}>0$$

anonymous · Answer

To satisfy x+4/-x-3 being greater than 0, I came up with x<-4 which would make 0>0, -4<x<-3 which would make it negative so I can't use that and -3<x.. so.. I dunno

hero · Answer

the answer is definitely -4<x<-3 for sure. I just checked it

hero · Answer

Nothing else will work except values between -4 and -3

anonymous · Answer

Ok.. I see.. Thanks guys for your help!

hero · Answer

Hey shark, the first thing we're supposed to do for this type of problem (which I didn't think to do right away) is find the critical points, then plot them on a number line. Then create intervals between them and test each one.

anonymous · Answer

Thanks Hero, I'll keep that in mind for next time