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OpenStudy (anonymous):
a carpenter is building a rectangular room with a fixed perimeter of 328 ft. what dimensions would yield the maximum area and what is the maximum area
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OpenStudy (anonymous):
On the other question with the 200ft rectangle use the guy's equation setup
OpenStudy (anonymous):
it would be 82 82 and total 6724 right
OpenStudy (anonymous):
The maximum area of a rectangle with a fix perimeter is a square with dimensions perimeter/4 by perimeter/4. In the case of this problem the dimensions of the square is 328/4 by 328/4 or 82 feet by 82 feet.
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