a carpenter is building a rectangular room with a fixed perimeter of 328 ft. what dimensions would yield the maximum area and what is the maximum area

Question

anonymous · Answer

On the other question with the 200ft rectangle use the guy's equation setup

anonymous · Answer

it would be 82
82 and total 6724 right

anonymous · Answer

The maximum area of a rectangle with a fix perimeter is a square with dimensions perimeter/4 by perimeter/4.  In the case of this problem the dimensions of the square is 328/4 by 328/4 or 82 feet by 82 feet.