Question

Let f(x) = sin 2x.Then the derivatives of f(x) equals ?

Answer 1

2cos(2x)

Answer 2

hmm there is no answer in the choice.

Answer 3

Choice given in the attachment.

Answer 4

spetzz is right, no matter what the choices are

Answer 5

Hmm but the choice given is a little confusing and complicated.I know that answer is correct.but there is no choice in it.

Answer 6

i cannot open the attachment for some reason, but let me make a guess

Answer 7

the answer is 2 cos(2x) so find the "double angle" formula for cos(2x) and see if that is one of the answers

Answer 8

problem is there are three to choose form

\[cos(2x)=1-2\sin^2(x)=2\cos^2(x)-1=\cos^2(x)-\sin^2(x)\]

Answer 9

hmm the choices given got give limit
wait i type out.

Answer 10

forget it
it is choice d

Answer 11

they are not asking for the answer. just what the definition is

Answer 12

wait a sec tha tis not right

Answer 13

what is not right? There are x and h in the choice.That making me confuse.

Answer 14

it is choice c and it was typed by someone whose math skills are limited

Answer 15

You mean the answer is choice c?

Answer 16

it should be
\[\lim_{h\rightarrow 0}\frac{\sin(2(x+h))-\sin(2x)}{h}\] in other works you should always write
\[\sin(x)\] not
\[\sinx\] but whatever. your math teacher wants c.

Answer 17

yes c. ask your math teacher why he or she does not think it necessary to put parentheses about the input of a function.
we write f(x) not fx and sin(x) not sinx