Question

Solve this equation.

9^(5x)=27

Answer 1

5x=3;
x=3/5

Answer 2

thats what i thought too but its incorrect

Answer 3

Put in terms of 3:
\[3^{2(5x)}=3^{3}\]
Take log base 3 of both sides:
\[\log_{3} (3^{10x})=\log_{3} 3^{3}\]
\[10x=3\]
\[x=3/10\]

Answer 4

or just try writing both with base 3 and to hell with the log

Answer 5

\[9^{5x}=3^{10x}\]
\[27=3^3\] so
\[3^{10x}=3^3\iff 10x=3\iff x=\frac{3}{10}\]