Question

y = (e^x + 4^3x)^6 find the derivative

Answer 1

\[y = (e^{x} + 4^{3x})^{6}\]

Answer 2

(e\[is \it 6(e ^{x} + 4^{3x)^{5}} * (2e ^{x} + \ln(4)(3) + 4^{3x})\]

Answer 3

?

Answer 4

\[6(e^x+4^{3x})^5\times (e^x+4^{3x}\ln(4)\times 3)\]

Answer 5

the derivative of
\[e^x\] is \[e^x\]

Answer 6

isnt it chain rule + product rule

Answer 7

the derivative of
\[b^x\] is \[b^x\times \ln(b)\] so by the chain rule the derivative of
\[4^{3x}\] is
\[4^{3x}\times \ln(4)\times 3\]

Answer 8

i made a mistake i think take the product rule derivative of the inner

Answer 9

no product here. i am fairly sure my answer is right. derivative is 6(blah)^5 times derivative of blah

Answer 10

yep thx