Does anyone know the answer..? I attached the question.

Question

anonymous · Answer

attachment

anonymous · Answer

I get 5(x+5)(x^2-5x+25) But idk if that's right

anonymous · Answer

I ended up with 5(x+5)(x^2+25)

anonymous · Answer

Why did I get a -5x and you didn't?

anonymous · Answer

5(x+5)(x^2-5x+25)
is correct

anonymous · Answer

I just want to double check. Lol

anonymous · Answer

5x^3 + 625 = 5x^3 + 5^4 = 5(x^3 + 5^3)

anonymous · Answer

:S Now I'm confused

anonymous · Answer

5(x^3 + 5^3)

U wanted one factor to be a sum of cubes, (x^3 + 5^3) is a sum of cubes

anonymous · Answer

Ok... But why did me and one other person get 5(x+5)(x^2-5x+25)? What did we do? Because I had a feeling that wasn't the sum of cubes but idk..

anonymous · Answer

You have factored the equation but as far as I can see, the question did not ask u to do that.

anonymous · Answer

Ohh.. How did you get your answer?

anonymous · Answer

Estudier your answer is incorrect. Taking a sum of cubes requires you to factor.

anonymous · Answer

I shoed u already above

5x^3 + 625 = 5x^3 + 5^4 = 5(x^3 + 5^3)

anonymous · Answer

:S

anonymous · Answer

$$5(x+5)(x ^{2}-5x+25) $$ is the correct answer.

anonymous · Answer

@starofathenry

"Estudier your answer is incorrect. Taking a sum of cubes requires you to factor."

What does "taking a sum of cubes" mean?

The question never said any such thing.

anonymous · Answer

"Factor the binomial so that one factor is the sum of cubes" is what it says..

anonymous · Answer

And I miss quoted - my mistake.

anonymous · Answer

If u just want to factor the equation it is a standard formulation or else just use Wolfram, it's not difficult http://www.wolframalpha.com/input/?i=5x^3+%2B625

anonymous · Answer

Here is a useful link - http://www.intmath.com/factoring-fractions/4-sum-difference-cubes.php

anonymous · Answer

I know about that site, but I didn't know if what I did was what i was sposed to do. That's why I asked humans.

anonymous · Answer

My answer satisfies the question.

anonymous · Answer

?

anonymous · Answer

In other words, "one factor is a sum of cubes"

anonymous · Answer

Lol me and @starofathenry were right... That answer, the one i got originally, was correct.

anonymous · Answer

Thanks for everyone's effort anyways

anonymous · Answer

Then the question should read "factor the equation using a sum of cubes"

There is no factor in your answer that is a "sum of cubes"