Question

Can someone help me evaluate this limit?
lim cosx/logx
x-->0+

Answer 1

Try using l'hopital's rule

Answer 2

The limit is 0.

Answer 3

How did it became 0?

Answer 4

Cosx near 0+ approaches 1 and Logx near 0+ goes to -infinity so the answer is 0.

Answer 5

I see. Thanks! :)

Answer 6

Using L'hopitale rule: you get -xsinx hence the limit of (-xsinx) as x tends towards zero is 0.