What is the distance between the points (3, 6) and (4, 2)?
\[Distance AB=\sqrt{(x_b-x_a)²+(y_b-y_a)²}\]
\[\sqrt{\Delta x ^{2}+\Delta y ^{2}}\]
just use the distance formula :)
pretty aegis and osirisis!
ok that seems kinda hard to do
\[\sqrt{(3-4)^2+(6-2)^2}\]
The formulas listed may look complicated but it really is plug and play. Just pay attention to your signs. The signs can give you the wrong answer in some problems.
play time is fun!
\[\sqrt{(4-3)^2 + (2-6)^2}\]
do you know why my expression and kenji's expression are the same? because (3-4)^2=(4-3)^2 and (6-2)^2=(2-6)^2
i didnt see that my previous answer was already given by myininaya XD
its good that you wrote it though it doesn't matter what x you take first just that you take the difference of the x's and same for y's
\[\sqrt{(difference of the x's)^2+(difference of the y's)^2}\]
yea. if the answer of the difference of the x's is negative, you'll just square it anyway so we'll get the same answer :)
:) yep yep
(sqrt of 17) or 4.1231(4 d.p)
yep gj richardson
Thanks Miyinaya!!
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