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OpenStudy (amistre64):
what have you tried and come up with?
OpenStudy (anonymous):
i tried -1/3 and that didnt work
OpenStudy (amistre64):
i take it those are y-2 and y+1 in the denominators?
OpenStudy (anonymous):
yes they are
OpenStudy (amistre64):
we can start this by something they call "cross multiplying" which is more descriptive than mathical
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OpenStudy (amistre64):
take the bottom of one side and multiply it to the top of the other side
OpenStudy (anonymous):
okay
OpenStudy (amistre64):
1 2
---- = ---- --> 1(y+1) = 2(y-2)
y-2 y+1
OpenStudy (amistre64):
what should our next step be?
OpenStudy (amistre64):
Hannah:
now that we have this
1(y+1) = 2(y-2)
what do you think we can do with it?
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OpenStudy (anonymous):
combine them?
OpenStudy (amistre64):
combine is a vague term, but its good that you are participating :)
lets multiply those numbers that are outside the (..)s thru like this:
1(y+1) = 2(y-2)
y+1 = 2y -4
now that its all adding; how do we get y all alone?
OpenStudy (anonymous):
subtract y?
OpenStudy (amistre64):
very good :) that is a step in the right direction for this
y+1 = 2y -4
-y -y
------------
1 = y - 4 ; now how should we get rid of the -4?
OpenStudy (anonymous):
add it!
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OpenStudy (amistre64):
yes!! :)
1 = y -4
+4 +4
---------
5 = y ; and thats our answer. Good job!